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How To Draw Complex Lewis Structures

An outline of how to detemine the "all-time" Lewis structure for an case, NOiii - is given below:

one. Determine the total number of valence electrons in a molecule
ii. Draw a skeleton for the molecule which connects all atoms using only single bonds.  In elementary molecules, the atom with the nearly available sites for bondng is usually placed key.  The number of bonding sites is detemined by because the number of valence electrons and the ability of an atom to aggrandize it's octet.  As you get ameliorate, you will exist able to recognise that certain groups of atoms prefer to bond together in a certain way.
3.  Of the 24 valence electrons in NOiii -, half-dozen were required to make the skeleton. Consider the remaining xviii electrons and place them then equally to fill the ocets of every bit many atoms equally possible (offset with the most electronegative atoms first then proceed to the more electropositive atoms).
iv.  Are the octets of all the atoms filled?   If not and so fill the remaining octets by making multiple bonds (make a lonely pair of electrons, located on a more electronegative cantlet, into a bonding pair of electrons that is shared with the atom that is electron defficient).
5. Cheque that you have the lowest FORMAL CHARGES possible for all the atoms, without violating the octet dominion;       (valence due east-) - (one/2 bonding e-) - (lone electrons).
IMPORTANT : no Lewis diagram is complete without formal charges.  Lewis diagrams are drawn to examine mechanisms so knowing which parts of a molecule are electron defficient (+) and which are electron rich (-) is vital.
It is best to have a formal charge of 0 for every bit many of the atoms in a structure every bit possible.
If a formal charge of 1- is located next to a formal charge of i+, the formal charges can ordinarily be minimized by having a lone pair of electrons, located on the cantlet with the i- charge get a bonding pair of electrons that is shared with the atom that has the 1+ formal accuse (this can be visualised in the aforementioned manner as the formation of multiple bonds were above).

CAUTION : octets tin exist expanded to minimise formal charges but only for atoms in the second row of the periodic table  (where northward=3 or greater).   For instance in our example, N cannot aggrandize its octet so keeps a formal accuse of ane+ and both singly bonded oxygens a formal charge of 1-.  If our molecule were So3 , however, it would be possible to minimize all formal charges by having the sulfur expand its octet.

6.  You may find that the best Lewis diagram (the one with the lowest formal charges and all octets satisfied) is given in a number of different ways.  For NOiii -, 3 dissimilar diagrams are given below.  From left to right they start with the most complete Lewis diagram to the nigh simplified.

Source: http://www.chem.ucalgary.ca/courses/351/Carey5th/Ch01/ch1-3depth.html

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